Getting free diskspace in python
To calculate the amount of free disk space in Python, you can use the os.stafvfs() function.
For some reason, I can never find the docs for os.statvfs() on the first or second try (it’s in the “Files and Directories” section in the os module), and I never remember how it works, so I’m posting this as a note to myself, and maybe to help out anybody else wanting to do the same thing.
A simple free space function can be written as:
import os def freespace(p): """ Returns the number of free bytes on the drive that ``p`` is on """ s = os.statvfs(p) return s.f_bsize * s.f_bavail
I use the f_bavail attribute instead of f_bfree, since the latter includes blocks that are reserved for the the super-user’s use.
I’m not sure, however, on the distinction between f_bsize and f_frsize.
Hey, thanks for this, I’d been using BFREE, and couldn’t figure out why I was getting inaccurate readings.
This was just what I was looking for. Thanks!
Thanks a lot! I’m new to python and I’m not a programmer, this piece of code save me time and it’s only 4 lines!
Thank again!
Thanks a fourth time, your google ranking is high
Perfect, I am going to use this to fix purge_builds.py from mozilla bug 512199
Be warned that ’statvfs’ is only available on UNIX.
Trying this code with Python 2.5 on Windows XP + SP3 yields following error:
AttributeError: ‘module’ object has no attribute ’statvfs’
tanks!!.
I thought solution the problem with a system call with the df command in linux with the command df, ‘;¬( but your solution is more elegant, does it work for all operating systems?(I mention this for what it says Dan Aquinas).
I think that the function will return the space in mega bytes would be:
import os
def freespace(p):
“”"
Returns the number of free MegaBytes on the drive that “p“ is on
“”"
s = os.statvfs(p)
return (s.f_bsize * s.f_bavail)/(1024*1024)